K Fatturi-Eżempju
Hex Kap Invita 1/2 - 13 żingu indurati 5
Bl-użu Torque = K x d x F K = .20
d = 0.50 in.
F = (75 fil-mija ta the prova load) = 0.75 x 85,000 psi x 0.1419 sq.in = 9045 lbs.
T = (0.20) (0.5 in.) (9045 lbs.) T= 905 in.-lbs. = 75 pied-lbs.
Fil il preċedenti example, aħna meqjusa K = 0.20. Dan huwa a kommfuq K fattur għal miksi biż-żingu qfieli.
We must issa nistaqsi xiex may jkollhom ġara jekk il person tinstalla l-qafla kieku jkollhom lubrikat eċċessivament the bolt u inwaqfet biha the same torque. Fil tali kundizzjonijiet, K may qatra biex a value ta 0.10.
Jekk T = K x d x F, then aħna jista ukoll tiskoraġġixximine il tagħbija minn qabel, F, fi il SAme mod.
F = T / (K x d)
F = 905 in.-lbs. / (0.10 x 0.50 in.) = 18,100 lbs.
Il- valur miksuba għal tagħna tagħbija minn qabel, 18,100 lbs., would jaqbeż il tensili saħħa ta a 1/2 - 13 grad 5
bolt.Momill-ġdid than likely the bolt in mistoqsija kieku jkollhom fallew. Il- eżatt l-oppostmay għandhom ukoll ġara resulting fi a lower clamp load than maybe required resulting fi għalqa ifalluumill-ġdid.
